Gustave Viaud
French photographer
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Summary
Gustave Viaud was born on April 25, 1836[1], in Rochefort[2]. He died on March 10, 1865[3], in Indian Ocean[4]. He worked as a photographer[5] and surgeon[6].
Key Facts
- Date of birth: 1836[7]
- Father: Théodore Viaud[8]
- Country of citizenship: France[9]
- Position held: director[10]
- Educated at: École de médecine navale de Rochefort[11]
- Sex or gender: male[12]
- Commons category: Gustave Viaud[13]
- Family name: Viaud[14]
- Given name: Gustave[15]
- Languages spoken, written or signed: French[16]
- Name in native language: Gustave Viaud[17]
- Sibling: Pierre Loti[18], Marie Bon[19]
- Copyright status as a creator: copyrights on works have expired[20]
FAQs
Where was Gustave Viaud born?
Gustave Viaud's place of birth was Rochefort[2].
Where did Gustave Viaud die?
Gustave Viaud passed away in Indian Ocean[4].
Who were Gustave Viaud's parents?
Gustave Viaud's father was Théodore Viaud[8].
What did Gustave Viaud do for work?
Gustave Viaud worked as a photographer[5] and surgeon[6].
Where did Gustave Viaud go to school?
Gustave Viaud was educated at École de médecine navale de Rochefort[11].